Question on C++-0x constexpr

[Ed Smith-Rowland]

I was toying around with constexpr in the standard library and tripped 
on this:
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// /bin/bin/g++ -std=c++0x -c template_constexpr.cpp
template<typename T>
class A
{
 static constexpr int foo() { return 666; }
};

template<typename E>
class B
{
 static constexpr int foo() { return e.foo(); }  //  Should the 
compiler be able to noodle this out?
 static constexpr int bar() { return E::foo(); }  //  Works fine.
private:
 E e;
};

template_constexpr.cpp: In static member function 'static int B<E>::foo()':
template_constexpr.cpp:16:5: error: invalid use of member 'B<E>::e' in 
static member function
template_constexpr.cpp:13:39: error: from this location
------------------------------------------------------------------------------------------------------------

Question, if you can use a member access operator to access a static 
member, shouldn't constexpr work through that method too?

Thanks,

Ed Smith-Rowland