(1x1)^1p1*0j1
_1
So in J
1x1 is e or 1 e to the power of 1
1p1 is ∏ or 1 ∏ to the power of 1
and
1j1 is 1+i and 0j1 is not 0 j to the power of 1 but 0 + 1 j (in other
words while i is used to represent the constant "Square Root of -1"
XjY is the complex number X + jY
so you can easily express Euler's identity
0 = 1+e to the power of i times ∏ in J as the constant 1x1 to the
power of the constant 1p1 times the complex number 0j1
0=1+(1x1)^1p1*0j1
1
which is true
Donna
[EMAIL PROTECTED]
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