Or 1+1x1^0j1p1 0
Henry Rich > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of dly > Sent: Saturday, June 17, 2006 9:30 AM > To: General forum > Subject: [Jgeneral] on finally remembering Euler's identity > > > > (1x1)^1p1*0j1 > _1 > > So in J > > 1x1 is e or 1 e to the power of 1 > > 1p1 is ∏ or 1 ∏ to the power of 1 > > and > > 1j1 is 1+i and 0j1 is not 0 j to the power of 1 but 0 + 1 j > (in other > words while i is used to represent the constant "Square Root of -1" > XjY is the complex number X + jY > > so you can easily express Euler's identity > > 0 = 1+e to the power of i times ∏ in J as the constant 1x1 to the > power of the constant 1p1 times the complex number 0j1 > > 0=1+(1x1)^1p1*0j1 > 1 > > which is true > > > Donna > [EMAIL PROTECTED] > > > > ---------------------------------------------------------------------- > For information about J forums see > http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
