Hello Raul;
Do you have a more detailed version of that statement? I can see how
?(arg,seed) is a function but I can't, in general, see how foo(arg,range)
would be a function, short of making the range argument a function of the
argument:
foo(arg,bar(arg))
which presupposes bar, which I don't see as a given.
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|\/| Randy A MacDonald | APL: If you can say it, it's done.. (ram)
|/\| [EMAIL PROTECTED] |
|\ | |If you cannot describe what you are doing
BSc(Math) UNBF'83 þas a process, you don't know what you're doing.
Sapere Aude | - W. E. Deming
Natural Born APL'er | Demo website: http://156.34.71.170/
-----------------------------------------------------(INTP)----{ gnat }-
----- Original Message -----
From: "Miller, Raul D" <[EMAIL PROTECTED]>
To: "General forum" <[email protected]>
Sent: Saturday, July 01, 2006 12:32 PM
Subject: RE: [Jgeneral] significant digits
Randy MacDonald wrote:
Actually ? _is_ a function. Some of its arguments are hidden.
Then, trivially, all relations are functions -- simply include
the range as a hidden part of the domain.
--
Raul
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