You have it right: there's only 1 cell for each operand, so they're paired. Now you have to consult the Dictionary so see what the -. verb will do with its operands. You see that it removes items of x that appear in y. So it removes the 2 and the 4s.
Henry Rich > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of Terrence Brannon > Sent: Sunday, April 22, 2007 5:19 PM > To: General forum > Subject: [Jgeneral] long-frame rationing when the shapes are not equal > > "long-frame rationing" is my term for what happens when the noun with > the larger frame has to broken up into n-cells to pair up with the > noun with the smaller frame. > > It is demonstrated here: > http://www.jsoftware.com/help/jforc/loopless_code_i_verbs_have > _r.htm#_Toc141157994 > > For the example: > 100 200 + i. 2 3 > > we see long-frame rationing occur when Henry says <QUOTE>The > longer-frame operand (the right one) is broken up into operand > 0-cells, each being paired with a copy of the shorter-frame operand > cell. Each paired _1-cell becomes a row of paired operand > cells:</QUOTE> > > so in my solution of 1 2 3 4 5 4 3 -. 2 4 > I am at the long-frame rationing step where the frames are the same > length, but I cannot pair them 1 for 1 because their shape is > different: > > > > Write out the entire expression: 1 2 3 4 5 4 3 -. 2 4 > Expand the verb rank(*1): -. b. 0 > 0 _ _ > > > Rank Calculation: > ---------------- > left-noun-rank: 1 right-noun-rank: 1 > left-verb-rank: _ right-verb-rank: _ > lesser left rank, lr = 1 lesser right rank, rr = 1 > > The verb will be applied to 1-cells of the left operand > and to 1-cells of the right operand. > > left-noun-shape: 7 right-noun-shape: 2 > > Frame Calulation(*2): > -------------------- > left-frame: lf = empty right-frame: rf = empty > > common frame: cf = empty > length of this common frame: rcf = 0 > -rcf = (_0) > > Operand Pairing: > --------------- > 1. Pair by common frame consisting of (-rcf)-cells: > > [1 2 3 4 5 4 3][2 4] > > 2. Pair by long-frame rationing. If the frames are the same length, > then you simply pair them 1 by 1. > > *** HELP NEEDED HERE *** > ---------------------------------------------------------------------- > For information about J forums see > http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
