On 6/6/07, Morten Kromberg <[EMAIL PROTECTED]> wrote:
Aha... So maybe I did miss something. I thought I was able to read enough J
to follow this discussion - I did not see any "normalization" and thought
the algorithm just used i.~. What did I miss?

In this case, i.~ is an example of normalization.

Hypothetically speaking, rounding might also count
as normalization, rounding only works when you can
take advantage of regular (presumably pre-defined)
intervals

--
Raul
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