Am Freitag, 8. Juli 2011, 20:35:57 schrieb Chris Poole: > On 8 Jul 2011, at 17:31, David Shaw <[email protected]> wrote: > > Yes. Note that the list-packets output shows the internal packed value: > > 6553600 should come out to 201. The default of 65536 would encode to > > 96. > > I do indeed get 201. Out of interest, how is that calculated?
https://tools.ietf.org/html/rfc4880#section-3.7.1.3 The count is coded into a one-octet number using the following formula: #define EXPBIAS 6 count = ((Int32)16 + (c & 15)) << ((c >> 4) + EXPBIAS); The above formula is in C, where "Int32" is a type for a 32-bit integer, and the variable "c" is the coded count, Octet 10. Hauke -- PGP: D44C 6A5B 71B0 427C CED3 025C BD7D 6D27 ECCB 5814
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