Thank you. On 8 Jul 2011, at 20:06, Hauke Laging <mailinglis...@hauke-laging.de> wrote:
> Am Freitag, 8. Juli 2011, 20:35:57 schrieb Chris Poole: >> On 8 Jul 2011, at 17:31, David Shaw <ds...@jabberwocky.com> wrote: >>> Yes. Note that the list-packets output shows the internal packed value: >>> 6553600 should come out to 201. The default of 65536 would encode to >>> 96. >> >> I do indeed get 201. Out of interest, how is that calculated? > > https://tools.ietf.org/html/rfc4880#section-3.7.1.3 > > The count is coded into a one-octet number using the following formula: > > #define EXPBIAS 6 > count = ((Int32)16 + (c & 15)) << ((c >> 4) + EXPBIAS); > > The above formula is in C, where "Int32" is a type for a 32-bit > integer, and the variable "c" is the coded count, Octet 10. > > > Hauke > -- > PGP: D44C 6A5B 71B0 427C CED3 025C BD7D 6D27 ECCB 5814 _______________________________________________ Gnupg-users mailing list Gnupg-users@gnupg.org http://lists.gnupg.org/mailman/listinfo/gnupg-users
