It seems that you are fighting the helpful infrastructure, but I can’t be sure
from what you’ve said.
You can (presumably) just do this:
For u := range streamOfUrls {
For w := range availableWorkers {
w.url = u
activeWorkers <- w
}
}
…but that is strange to me. Why not just have every worker loop for urls on its
input channel:
for I := 0; I < workers; i++ {
go Worker(urlChannel)
}
:
func Worker (uChan chan url) {
for u:= range uChan {
do work with u
}
}
:
for ...range of urls… {
urlChan <- nextUrl
}
close(urlChan) // will terminate all workers after their last task is assigned
From: <golang-nuts@googlegroups.com> on behalf of
<omarshariffdontlik...@gmail.com>
Date: Wednesday, November 30, 2016 at 9:07 AM
To: golang-nuts <golang-nuts@googlegroups.com>
Subject: [go-nuts] synchronise read from two channels
Hi, I'm having a bit of a slow day... I'm trying to synchronise two reads from
two channels and can't get my fuzzy head round the problem.
I have a channel containing urls (which will be feed periodically by a named
pipe by another program) and I have a cannel which consists of a pool of
available workers. I'd like to synchronise these and put a worker into a third
channel for active workers if there is a url in the channel and if there is an
available worker.
Ideally I'd be able to do something like:
go func(urlChan <-chan *url.URL, availableWorkerChan <-chan *worker,
activeWorkerChan chan<- *worker){
for {
select{
case w := <-availableWorkerChan && w.Url = <-urlChan:
activeWorkersChan <- w
}
}
}(a, b, c)
But obviously thats not right!
Can anyone offer my tired brain a clue?
Cheers!
Ben
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