Hi,
GFW
1 0.017971305190311
2 0.000000000000000
3 0.000000000000000
4 -0.017971305190311
5 -127.620375523875420
6 50.406626367301044
=========================
Considering width as W, Height as H
Image Width = W
Image Height = H
Top Left point Lat = Line 6 -> 50.406626367301044
Lng = Line 5 -> -127.620375523875420
Top RIght point Lat = Line 6 -> 50.406626367301044
Lng = ( W*Line1 width of a pixle ) -> 0.017971305190311 ) +
Line 5 -
> -127.620375523875420
Bottom Left point Lat = Line 6 -> 50.406626367301044 + H *
Line4 (height of pixel) -> -0.017971305190311
Lng = Line 5 -> -127.620375523875420
Bottom right point Lat = Line 6 -> 50.406626367301044 + H *
Line4 height of pixel ) -> -0.017971305190311
Lng = W*Line1 (0.017971305190311) + Line 5 ->
-127.620375523875420
But for this, one should know at least width and height of image. Once
we get the image is there a way to find out width and height
dynamically ?
-Thanks
Manohar
On Jul 30, 7:32 pm, Juguang XIAO <[email protected]> wrote:
> Ian, You can crack it, I believe. :-) Using spherical trigonometry, flash's
> DisplacementMapFilter and your Britainis-Got-Talent brain. :-)
>
> Juguang
>
> On Fri, Jul 31, 2009 at 3:17 AM, I_Watkins <[email protected]> wrote:
>
> > Shouldn't have any problem after you reproject these over Google maps.
>
> > I'll have a go at it over the next few days, should hopefully be
> > straight forwards.
>
> > Cheers
>
> > Ian
>
> --
> =============
> Juguang XIAO
> Beijing, China
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