Gabriele N. wrote:
> Thanks for the interesting explanation.
> I did then so:
>
> r.mapcalc "A_new = (double(A)) and r.mapcalc "B_new = (double(B))
>
> and then
>
> r.mapcalc "output" = "(("A_new" * 10000)+("B_new" ))"
The same result can be achieved with one command:
r.mapcalc "output = A * 10000.0 + B"
The multiply will cause A to be converted to double to match the other
argument (floating-point constants are double unless an explicit "f"
suffix is given), the multiply will yield a double result, and the
addition will convert B to double to match this.
--
Glynn Clements <gl...@gclements.plus.com>
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