With the makefile
foobar:
echo \\\foobar
why
C:\Temp>make foobar
\\foobar
Where is this explained in the manual? echo \\\foobar produces 3 slashes, so it
must be make that is stripping off one slash. Therefore it must be that \ is a
special character in this context. OK, then the first \ escapes the second
one, the second one is printed, then why doesn't the third one escape the "f"
and produce "f". It should be either \\\foobar, or \oobar, but I don't see how
this should produce \\foobar ??? Where is this explained in the manual?
Thank you very much.
Mark
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