OK, let me make sure I am not confused: Are you saying that on Unix:
>echo \\\foobar \foobar And that is why you expected that? -----Original Message----- From: Paul Smith [mailto:[email protected]] Sent: Sunday, February 07, 2010 6:21 AM To: Mark Galeck (CW) Cc: [email protected]; [email protected] Subject: RE: why does command echo \\\foobar print \\foobar On Sun, 2010-02-07 at 06:02 -0800, Mark Galeck (CW) wrote: > That's the whole point, you said before, it _should_ be \foobar, that > is what you had "expected", obviously based on some knowledge about > GNU make's behavior. No, not "obviously". Please don't leap to conclusions. _______________________________________________ Help-make mailing list [email protected] http://lists.gnu.org/mailman/listinfo/help-make
