Nevermind, I just saw the 4'x8'. But if anyone feels like posting hexamath, feel free to do so.
On Friday, August 1, 2014 3:28:34 AM UTC-4, James Cockerham wrote: > > The top entrance is 8ft wide into a 12 deep covered pit. 6' of the pit is > dug out, the timbers will rest on unexcavated soil and give another 6 feet > in height. Beyound the hexahole in the ceiling with fire pit below, I'm > thinking around 10' of sheltered space with 4' of that being a shored up > sleeping bench, kind of like this. > > > <https://lh5.googleusercontent.com/-uBF9fXzzfj8/U9s_BmwPSBI/AAAAAAAAFVU/6UdDSCKLAbA/s1600/hexapitmath.jpg> > > and this.. > > > <https://lh6.googleusercontent.com/-6cMkl_8rUro/U9tATFwailI/AAAAAAAAFVc/TGM5Vldp1dQ/s1600/day2-01.jpg> > > I need a math refresher. If the portal is 8ft from I to I of the hexagon, > what is the length from < to > of the hexagon? The hypotenuse of those thin > air triangles, or the length of the shored up portal edges? > > -- You received this message because you are subscribed to the Google Groups "hexayurt" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/hexayurt. For more options, visit https://groups.google.com/d/optout.
