Count your hops. Holding network speed constant, each hop increases the transit time by a multiple.
Let x = rated network speed. One hop = X/1 Two hops = X/2 Three hops = X/3 And so on. In other words: consider a packet traveling directly from point A to point C. It arrives at point C at network speed. Now insert point B. The packet arrives at B in the same elapsed time as before, but must traverse the network again to arrive at C. Hence, the elapsed transit time is doubled. Of course, it is a bit more complicated but you should get the idea. HTH and good luck. -----Original Message----- From: IBM Mainframe Discussion List [mailto:[EMAIL PROTECTED] On Behalf Of François Paré Sent: Friday, June 20, 2008 8:06 AM To: [email protected] Subject: Re: Slow FTP transfer from z/OS to Unix Rob, We tried TRACERTE but there is no problem there, one hop a couple of milliseconds. We will work on traces and thank you for all the tracks you gave. François Paré NOTICE: This electronic mail message and any files transmitted with it are intended exclusively for the individual or entity to which it is addressed. The message, together with any attachment, may contain confidential and/or privileged information. Any unauthorized review, use, printing, saving, copying, disclosure or distribution is strictly prohibited. If you have received this message in error, please immediately advise the sender by reply email and delete all copies. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
