JES2 runs under a user  id. The RACF address space runs under a user id. In
fact nearly all work after the initialisation of SAF (which happens very
soon after MSI) will run under a user id. Even initiators start work under a
user id (although they subsequently lose that id).
In addition, any started task that is submitted using SUB=MSTR, (such as
LLA, VLF ICSF and others) will start under a user id. Yet all these address
spaces do NOT show a user id in SDSF DA or using the MVS DISPLAY command.
Lennie Dymoke-Bradshaw
https://rsclweb.com 
'Dance like no one is watching. Encrypt like everyone is.'

-----Original Message-----
From: IBM Mainframe Discussion List <[email protected]> On Behalf Of
Seymour J Metz
Sent: 29 November 2021 16:28
To: [email protected]
Subject: Re: Display user for started tasks started under Master subsystem

There are some tasks that you need to start when there is no ESM active.
What user id would you expect for, e.g., JES2, RACF?


--
Shmuel (Seymour J.) Metz
http://mason.gmu.edu/~smetz3

________________________________________
From: IBM Mainframe Discussion List [[email protected]] on behalf of
Lennie Dymoke-Bradshaw [[email protected]]
Sent: Monday, November 29, 2021 9:27 AM
To: [email protected]
Subject: Display user for started tasks started under Master subsystem

I am looking at an SDSF DA display showing active address spaces.



The column 'Owner' shows the user id associated with the address space.
However, for those address spaces which are subsystems or which are started
under the master subsystem, the user id is not shown.



If I display address spaces using the MVS display command D A,<name> I get a
similar result. The user id of the address space is not shown.



While I am aware, this has been the case for some time, I am confused as to
why this is. For SDSF I had thought it was simply that the id was extracted
from JES2 and of course the subsystems have no such JES2 control blocks. But
the MVS display command does not have that restriction.



Does anyone have any insight?

Does anyone know how to determine the user id of these address spaces using
commands?





Lennie Dymoke-Bradshaw

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'Dance like no one is watching. Encrypt like everyone is.'








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