Because it isn't the 32nd day of the month?
In about 180 million years we will be up to a 25 hour day, due to the
tides from the moon slowing the earth down.
So, about every 2083 years we add a second to each day.

On Thu, May 4, 2017 at 11:42 AM, Paul Gilmartin
<[email protected]> wrote:
> On Thu, 4 May 2017 07:53:24 -0500, Dana Mitchell wrote:
>
>>This has been discussed before and is explained very well in this IBM techdoc:
>>
>>https://www-03.ibm.com/support/techdocs/atsmastr.nsf/WebIndex/WP102081
>>
>>Depending on if you need to be exactly on time after the leap second occurs, 
>>or can tolerate taking a while to 'smear' the time to the new value,  STP 
>>gives you the choice of spinning whilst waiting for an extra leap second to 
>>be inserted (Category 1)   or slowly steering the time (Category 2):
>>
>>STP will begin to slowly steer the mainframe time to the new value. It takes 
>>approximately 7 hours for STP to steer out a one second delta.
>>
> That depends on *not* running the (E)TOD clock at the TAI rate and with
> the 10-second offset that is otherwise IBM's recommendation.
>
> Amazon and Google have the pragmatic approach of a smear centered on the
> leap secoond, making the maximum deviation from UTC a half second rather
> than a full second.  I suppose this could be achieved with the HMC/STP by
> using Google or Amazon as a reference.  If they come to agree on the interval.
>
> Steering the TOD clock would break applications (are there any?) that depend
> on microsecond accuracy of STCK.
>
> Making multiple microscopic adjustments to CVTLSO throughout a smearing
> interval has other sorts of complexity.
>
> Why does a 24-hour adjustment for a leap year cause less disruption than
> a single leap second?
>
> -- gil
>
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-- 
Mike A Schwab, Springfield IL USA
Where do Forest Rangers go to get away from it all?

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