For sure you'd need some kind of a circuit between the PIR and the high-current VBUS. If the phone is normally not charging, it will eventually run out of its own battery. If that's something that matters in your case, you may want to plug it into a wall adapter and have the PIR cut-off power instead of enabling it. Don't know about a good electronic forum. There appear to be many of them.
On Sun, May 4, 2014 at 2:20 AM, ultimoamore <[email protected]> wrote: > On Sunday, May 4, 2014 9:28:05 AM UTC+2, Ytai wrote: >> >> And you may want to inert the polarity, so that the phone normally >> charges. >> > (I suppose you meant "inVert the polarity) Why? In this way the batteries > would drain very quickly... > > I'm worried about the current the PIR would be able to sustain... the > phone might not see enough current to trigger the "charging" event. maybe > I need also a mosfet? > > (I understand this is going OT... can someone suggest a good electronic > forum?) > > > >> -- > You received this message because you are subscribed to the Google Groups > "ioio-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/ioio-users. > For more options, visit https://groups.google.com/d/optout. > -- You received this message because you are subscribed to the Google Groups "ioio-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/ioio-users. For more options, visit https://groups.google.com/d/optout.
