Tony Hain wrote:

you are right that no packet gets duplicated in this scenario and
ultimately the number of packets in equals the number out. But the
attack relies of the technique of stuffing packets in over an extended
interval and then releasing them all towards the destination in a much
shorter time interval.

This makes no sense. The latency is the same for the entire packet chain, so
the delay between the first and last should be the same at the exit, modulo
normal queuing jitter.


Here's an example:

The first N packets do       Src -> A -> B -> A -> B -> A -> B ->Dst

The second set of packets do Src -> A -> B -> A -> B ->Dst

The third set of packets do  Src -> A -> B ->Dst

Now if you get everything _just right_ in terms of timings (and that will be tricky) you can get all 3 sets of packets released to the destination in a burst that is up to 3 x the input packet rate in this example.

And, yes there are probably simpler DDOS attacks out there! I was simply trying to explain what the original work and Joe's draft referred to when they referred to "capacitance attacks".


regards,

  Geoff



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