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https://issues.apache.org/jira/browse/CALCITE-1016?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=15051601#comment-15051601
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Julian Hyde commented on CALCITE-1016:
--------------------------------------
MySQL agrees with Oracle:
{noformat}
mysql> select count(*) from days where 1=0;
+----------+
| count(*) |
+----------+
| 0 |
+----------+
1 row in set (0.00 sec)
mysql> select count(*) from days where 1=0 group by '1';
Empty set (0.00 sec)
{noformat}
(MySQL does not support 'group by 1' or 'group by ()'.)
> What should "GROUP BY 1" return on an empty table?
> --------------------------------------------------
>
> Key: CALCITE-1016
> URL: https://issues.apache.org/jira/browse/CALCITE-1016
> Project: Calcite
> Issue Type: Bug
> Reporter: Julian Hyde
> Assignee: Julian Hyde
>
> What should "GROUP BY 1" return on an empty table? Calcite currently returns
> 0 rows. I am hearing claims that according to standard SQL it should return 1
> row.
> Here is what Oracle 11.2.0.2.0 does.
> {noformat}
> SQL> select count(*) from emp where 1 = 0;
> COUNT(*)
> ----------
> 0
> SQL> select count(*) from emp where 1 = 0 group by ();
> no rows selected
> SQL> select count(*) from emp where 1 = 0 group by 1;
> no rows selected
> SQL> select count(*) from emp;
> COUNT(*)
> ----------
> 14
> SQL> select count(*) from emp group by ();
> COUNT(*)
> ----------
> 14
> SQL> select count(*) from emp group by 1;
> COUNT(*)
> ----------
> 14
> {noformat}
> I had expected {code}select count(*) from emp where 1 = 0 group by (){code}
> would return 1 row, but it returns 0, like {code}group by 1{code}.
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