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Set all of your environment variables in jserv.properties file as
wrapper.bin=C:\jserv....\*.class some thing like this..
Then.. you program can just access variable as dynamically..
Janga Aliminati
Vidya Ramachandran wrote:
>
> ----------------------------------------------------------------
> BEFORE YOU POST, search the faq at <http://java.apache.org/faq/>
> WHEN YOU POST, include all relevant version numbers, log files,
> and configuration files. Don't make us guess your problem!!!
> ----------------------------------------------------------------
>
> Dear Fellow Members,
>
> I need your help desperately....I had posted this query earlier, but haven't
> received a solution for it as yet.
> I'm hoping for one now.
>
> This is my problem :-
> I am using ApacheServ 1.1.2 on Windows NT 4.0.
>
> I want to store some configuration parameters in a config file.
> How can I read the path of this config file.
>
> I am storing it in Environment variable and fetching the value by
> System.getProporty method.
> But I am getting null as the value.
>
> I looked in the archive and found this :-
> "The file jserv.properties contains two under-emphasised variables -
> wrapper.env.copy and wrapper.env.copyall. The default for
> wrapper.env.copyall is false. I disagree with this, as it prevents JServ
> from having access to your environment variables. If you are having
> strange exceptions thrown like UnsatisfiedLinkError, set this variable to
> true.
> If your server is configured properly the problem should be resolved.
> wrapper.env.copy allows you to copy individual environment variables for
> use by the JVM. ie: wrapper.env.copy=PATH"
>
> I have tried this as well but nothing seems to work...I'm at a dead end !!
> Please help me...
>
> regards
> Vidya
>
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