> Date:         Mon, 15 Jul 2002 12:38:08 -0700
> From: Mark Hood <[EMAIL PROTECTED]>
>
> In this representation the vector (A, B, C) is the normal to the plane.  If
> you extend this normal from the origin and go a distance D from the origin
> backwards along the normal direction you'll get a point that intersects the
> plane.

Assuming the normal is unit length.  If not, the distance of the point from the
origin is -D/sqrt(A^2 + B^2 + C^2).

-- Mark Hood

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