kamalcph commented on code in PR #16602:
URL: https://github.com/apache/kafka/pull/16602#discussion_r1759255906


##########
core/src/main/java/kafka/log/remote/RemoteLogManager.java:
##########
@@ -620,6 +631,23 @@ private Optional<Integer> maybeLeaderEpoch(int 
leaderEpoch) {
         return leaderEpoch == RecordBatch.NO_PARTITION_LEADER_EPOCH ? 
Optional.empty() : Optional.of(leaderEpoch);
     }
 
+    public AsyncOffsetReadFutureHolder<Either<Exception, 
Option<FileRecords.TimestampAndOffset>>> asyncOffsetRead(
+            TopicPartition topicPartition,
+            Long timestamp,
+            Long startingOffset,
+            LeaderEpochFileCache leaderEpochCache,
+            Supplier<Option<FileRecords.TimestampAndOffset>> searchLocalLog) {
+        CompletableFuture<Either<Exception, 
Option<FileRecords.TimestampAndOffset>>> taskFuture = new CompletableFuture<>();
+        Future<Void> jobFuture = remoteStorageReaderThreadPool.submit(
+                new RemoteLogOffsetReader(this, topicPartition, timestamp, 
startingOffset, leaderEpochCache, searchLocalLog, result -> {
+                    TopicPartitionOperationKey key = new 
TopicPartitionOperationKey(topicPartition.topic(), topicPartition.partition());
+                    taskFuture.complete(result);
+                    delayedRemoteListOffsetsPurgatory.checkAndComplete(key);
+                })
+        );
+        return new AsyncOffsetReadFutureHolder<>(jobFuture, taskFuture);

Review Comment:
   Thanks for the review! 
   
   The reason for maintaining 2 futures: jobFuture and taskFuture. They are 
required to trigger the delayed operation completion 
(delayedRemoteListOffsetsPurgatory#checkAndComplete(key)) in the same 
remote-log-reader thread. When all the partitions results are received, then 
the delayedOperation gets completed.
   
   We have ActionQueue to complete the pending actions but the LIST_OFFSETS 
request can be served by any replica (least loaded node). If the node serving 
the request doesn't have leadership for any of the partitions, then the result 
might not be complete.



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