if ( obj.jquery )
  //obj is an jQuery object

jquery property gives the jQuery version, that is always an non empty
string


On Sep 18, 1:50 am, lrbabe <lrb...@gmail.com> wrote:
> mmmh... overwriting the constructor property doesn't sound like a
> great idea to me.
> What about all the code that has been written by developers expecting
> the constructor to be what it is supposed to be: Object
>
> You could use other particular properties of any jQuery object: they
> are not arrays but they have a length property:
> !$.isArray($obj) && ($obj.length !== undefined)
>
> It is not perfect but it can help.
>
> On Sep 17, 8:04 pm, Nico <nicolas.deve...@gmail.com> wrote:
>
> > Hi,
>
> > I first posted this message on the jquery-en group, but it should
> > probably be posted here, so here am I.
>
> > In some cases, I have to check if a variable is a jQuery object or
> > not. Usually, to check a variable type, I use the "constructor"
> > property
> > (when I can't use typeof, which is not accurate).
> > In case of jQuery, the constructor property equals Object, so I can't
> > use it.
> > When I create a jQuery Object, it's known by javascript as an object,
> > and it behaves like a function.
>
> > Would it be possible to add something so we could get a true with this
> > example :
>
> > $([]).constructor === jQuery
>
> > This would be great, no ?? The only change to do is to add in the
> > beginning of jQuery.fn.init method the line :
>
> > this.constructor = jQuery;
>
> > This way, all jQuery's objects "constructor" property equals jQuery. I
> > quickly tried this, and I met no bugs.
>
> > Any arguments against this ?
>
> > Nico
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