Hello there,
In my current project, I have a similar need to detect if a variable
is a jQuery object or not.
I finaly decided to add a $.isJQuery() method to jQuery namespace that
could acts like a regular $.isArray or $.isFunction.
Not sure, this is the best way to do this but I used something like:
$.isJQuery = function(o){
try {
// no matter the checked method, just ensure calling it not
raise an error
o.is();
return true;
}
catch (e) {
return false;
}
};
That did the trick for me.
Best regards,
On Sep 17, 8:04 pm, Nico <nicolas.deve...@gmail.com> wrote:
> Hi,
>
> I first posted this message on the jquery-en group, but it should
> probably be posted here, so here am I.
>
> In some cases, I have to check if a variable is a jQuery object or
> not. Usually, to check a variable type, I use the "constructor"
> property
> (when I can't use typeof, which is not accurate).
> In case of jQuery, the constructor property equals Object, so I can't
> use it.
> When I create a jQuery Object, it's known by javascript as an object,
> and it behaves like a function.
>
> Would it be possible to add something so we could get a true with this
> example :
>
> $([]).constructor === jQuery
>
> This would be great, no ?? The only change to do is to add in the
> beginning of jQuery.fn.init method the line :
>
> this.constructor = jQuery;
>
> This way, all jQuery's objects "constructor" property equals jQuery. I
> quickly tried this, and I met no bugs.
>
> Any arguments against this ?
>
> Nico
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"jQuery Development" group.
To post to this group, send email to jquery-dev@googlegroups.com
To unsubscribe from this group, send email to
jquery-dev+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/jquery-dev?hl=en
-~----------~----~----~----~------~----~------~--~---
