Mickael, I'd use Andrea's solution instead for the same reasons: any
object could have an .is() method.
On Sep 19, 5:16 am, Mickael DANIEL <daniel.mick...@gmail.com> wrote:
> Hello there,
>
> In my current project, I have a similar need to detect if a variable
> is a jQuery object or not.
>
> I finaly decided to add a $.isJQuery() method to jQuery namespace that
> could acts like a regular $.isArray or $.isFunction.
>
> Not sure, this is the best way to do this but I used something like:
> $.isJQuery = function(o){
> try {
> // no matter the checked method, just ensure calling it not
> raise an error
> o.is();
>
> return true;
> }
> catch (e) {
> return false;
> }
>
> };
>
> That did the trick for me.
>
> Best regards,
>
> On Sep 17, 8:04 pm, Nico <nicolas.deve...@gmail.com> wrote:
>
> > Hi,
>
> > I first posted this message on the jquery-en group, but it should
> > probably be posted here, so here am I.
>
> > In some cases, I have to check if a variable is a jQuery object or
> > not. Usually, to check a variable type, I use the "constructor"
> > property
> > (when I can't use typeof, which is not accurate).
> > In case of jQuery, the constructor property equals Object, so I can't
> > use it.
> > When I create a jQuery Object, it's known by javascript as an object,
> > and it behaves like a function.
>
> > Would it be possible to add something so we could get a true with this
> > example :
>
> > $([]).constructor === jQuery
>
> > This would be great, no ?? The only change to do is to add in the
> > beginning of jQuery.fn.init method the line :
>
> > this.constructor = jQuery;
>
> > This way, all jQuery's objects "constructor" property equals jQuery. I
> > quickly tried this, and I met no bugs.
>
> > Any arguments against this ?
>
> > Nico
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