Now I understand you. 'id' was in so many places I thought you were
confused about how to use them. After rereading, I see you refer to
<image> as the tag, did you really mean that or did you use <img> in
your html? <image> is not the proper HTML tag name, it is <img>
On Dec 9, 11:24 pm, JQueryProgrammer <[EMAIL PROTECTED]> wrote:
> Well I think you did not understand my quest correctly. As I said I
> cannot use the id for selector as my id is getting runtime generated.
> So i am using a custom attribute "myimgid" to select the element. I
> tried to use event.preventDefault too. but still its firing the
> original attached event. Any help would be appreciated.
>
> On Dec 9, 6:24 pm, donb <[EMAIL PROTECTED]> wrote:
>
>
>
> > I don't think you're really understanding the selector syntax.
> > The 'id' is unique (or is supposed to be) and starts with a '#' in a
> > selector, and
> > the css syntax uses a name and value pair to set the attribute. So:
>
> > $("#myimage).css('display", "inline"); // or "block"
>
> > or try this alternative:
>
> > $("#myimage).show();
>
> > or possibly:
>
> > $("#myimage).toggle()
>
> > The last one displays when hidden and hides if already visible. I
> > assume that 'myimg' is not something you really intended to use for
> > the selector.
>
> > On Dec 9, 7:16 am, JQueryProgrammer <[EMAIL PROTECTED]> wrote:
>
> > > <image id="myimage" myimgid="myimageid" src="baloon.jpg" />
>
> > > I want to check the style display for this image. I am doing as:
>
> > > $("image[myimgid='myimageid']").css("display");
>
> > > but its coming undefined. I cannot check it with id as my id is
> > > getting runtime generated. Please help.- Hide quoted text -
>
> - Show quoted text -
