I was trying to do this this morning and came across this thread
vec = map(x -> ismatch(r"regex_expression", x), df[:column])
vec = convert(DataArray{Bool}, vec)
subset(df, results)
Seems to work just fine. There isn't currently an easier way to do this,
is there?
On Thursday, July 4, 2013 10:45:13 AM UTC-4, S Wade wrote:
>
> John,
>
> I have a string column that I'd like to filter by (using a regex
> ismatch()). Is there a way to express this via subset() or expr indexing?
>
> Thanks,
> Wade
>
> On Jul 4, 2013, at 9:50 AM, John Myles White <[email protected]
> <javascript:>> wrote:
>
> > This is probably just a gap in the docs:
> >
> > df = DataFrame(a = 1:5, b = 6:10)
> > df[:(a .< 4), :]
> > subset(df, :(a .< 4))
> >
> > -- John
> >
> > On Jul 4, 2013, at 9:37 AM, S Wade <[email protected] <javascript:>>
> wrote:
> >
> >> Hi all,
> >>
> >> I'm sure I'm just missing this in the readme but I can't seem to find a
> way to filter a data frame either through indexing or subset() as I would
> in R. Can someone provide a hint?
> >>
> >> Thanks,
> >> Wade
> >
>
