Why not just use straight indexing like below?

df[Bool[ismatch(r"a", x) for x in df[:Column]], :]

 -- John

On Jul 14, 2014, at 9:32 AM, Andrew G <[email protected]> wrote:

> vec = map(x -> ismatch(r"regex_expression", x), df[:column])
> vec = convert(DataArray{Bool}, vec)
> subset(df, results)
> 

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