Why not just use straight indexing like below? df[Bool[ismatch(r"a", x) for x in df[:Column]], :]
-- John On Jul 14, 2014, at 9:32 AM, Andrew G <[email protected]> wrote: > vec = map(x -> ismatch(r"regex_expression", x), df[:column]) > vec = convert(DataArray{Bool}, vec) > subset(df, results) >
