That's a lot more elegant, thanks!
On Monday, July 14, 2014 9:43:40 AM UTC-4, John Myles White wrote: > > Why not just use straight indexing like below? > > df[Bool[ismatch(r"a", x) for x in df[:Column]], :] > > -- John > > On Jul 14, 2014, at 9:32 AM, Andrew G <[email protected] <javascript:>> > wrote: > > > vec = map(x -> ismatch(r"regex_expression", x), df[:column]) > > vec = convert(DataArray{Bool}, vec) > > subset(df, results) > > > >
