[julia-users] type for lufact()

[Alan Crawford]

I would like to setup a type stable function where one of the arguments is 
the result of lufact(A) where A::Array{Float64,2}. 

Here is code I wrote to test this out:

A = rand(100,100);
f = rand(100,1);
luA = lufact(A);
typeof(luA)
function test(f::Vector{Float64},luA::LU{Float64,Array{Float64,2}}) 
       \(luA,f) 
end

The output i get is:

*typeof(luA)*

*LU{Float64,Array{Float64,2}} (constructor with 1 method)*


*julia> **function 
test(f::Vector{Float64},luA::LU{Float64,Array{Float64,2}}) *

*         \(luA,f) *

*       end*

*ERROR: LU not defined*


I am working in Julia 0.3.7. I am relatively new to Julia, so I imagine I 
am missing something quite simple...