Thanks!
On Saturday, 11 April 2015 14:14:14 UTC+1, Kristoffer Carlsson wrote:
>
> It should work if you write "using Base.LinAlg" first
>
> On Saturday, April 11, 2015 at 2:29:57 PM UTC+2, Alan Crawford wrote:
>>
>> I would like to setup a type stable function where one of the arguments
>> is the result of lufact(A) where A::Array{Float64,2}.
>>
>> Here is code I wrote to test this out:
>>
>> A = rand(100,100);
>> f = rand(100,1);
>> luA = lufact(A);
>> typeof(luA)
>> function test(f::Vector{Float64},luA::LU{Float64,Array{Float64,2}})
>> \(luA,f)
>> end
>>
>> The output i get is:
>>
>> *typeof(luA)*
>>
>> *LU{Float64,Array{Float64,2}} (constructor with 1 method)*
>>
>>
>> *julia> **function
>> test(f::Vector{Float64},luA::LU{Float64,Array{Float64,2}}) *
>>
>> * \(luA,f) *
>>
>> * end*
>>
>> *ERROR: LU not defined*
>>
>>
>> I am working in Julia 0.3.7. I am relatively new to Julia, so I imagine I
>> am missing something quite simple...
>>
>
