It should work if you write "using Base.LinAlg" first
On Saturday, April 11, 2015 at 2:29:57 PM UTC+2, Alan Crawford wrote:
>
> I would like to setup a type stable function where one of the arguments is
> the result of lufact(A) where A::Array{Float64,2}.
>
> Here is code I wrote to test this out:
>
> A = rand(100,100);
> f = rand(100,1);
> luA = lufact(A);
> typeof(luA)
> function test(f::Vector{Float64},luA::LU{Float64,Array{Float64,2}})
> \(luA,f)
> end
>
> The output i get is:
>
> *typeof(luA)*
>
> *LU{Float64,Array{Float64,2}} (constructor with 1 method)*
>
>
> *julia> **function
> test(f::Vector{Float64},luA::LU{Float64,Array{Float64,2}}) *
>
> * \(luA,f) *
>
> * end*
>
> *ERROR: LU not defined*
>
>
> I am working in Julia 0.3.7. I am relatively new to Julia, so I imagine I
> am missing something quite simple...
>
