f(floor(x); args...) should work. On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen < linush...@gmail.com> wrote:
> I am looking for a way to automatically pass on all keyword arguments > through a function. Naively I would like to be able to do something like > this: > > f(x::Int; y::Int=5, z::Int=3) = x+y+z > f(x::Float64; args...) = f(floor(x), args...) > > But that doesn't work currently (actually, it causes StackOverflowError in > 0.4.0). So far I've been using the following instead: > > f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) > > But that gets messy very quickly if there are several keyword arguments to > handle. Does anyone know of a clean way to do this? > > >
