This worked! Didn't realize you could use ";" when calling functions.
On Tuesday, July 21, 2015 at 4:49:36 PM UTC+2, Stefan Karpinski wrote: > > f(floor(x); args...) should work. > > On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen < > [email protected] <javascript:>> wrote: > >> I am looking for a way to automatically pass on all keyword arguments >> through a function. Naively I would like to be able to do something like >> this: >> >> f(x::Int; y::Int=5, z::Int=3) = x+y+z >> f(x::Float64; args...) = f(floor(x), args...) >> >> But that doesn't work currently (actually, it causes StackOverflowError >> in 0.4.0). So far I've been using the following instead: >> >> f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) >> >> But that gets messy very quickly if there are several keyword arguments >> to handle. Does anyone know of a clean way to do this? >> >> >> >
