On Tuesday, July 21, 2015 at 7:14:02 AM UTC-7, Linus Härenstam-Nielsen wrote: > > I am looking for a way to automatically pass on all keyword arguments > through a function. Naively I would like to be able to do something like > this: > > f(x::Int; y::Int=5, z::Int=3) = x+y+z > f(x::Float64; args...) = f(floor(x), args...) > > But that doesn't work currently (actually, it causes StackOverflowError in > 0.4.0). So far I've been using the following instead: > > f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) > > But that gets messy very quickly if there are several keyword arguments to > handle. Does anyone know of a clean way to do this? > > > I think you're getting the stack overflow because your call to floor doesn't convert to Int, so f(x::Float64; args...) keeps getting called recursively. What happens if you change your second method to
f(x::Float64, y::Int=5, z::Int=3) = f(floor(Int, x), y=y, z=z) instead?
