pointer() is using printf() type of format, and GCC compiler (Debian 14.2.0-17) is not happy about this:
lib/vsprintf.c:2466:17: error: function ‘pointer’ might be a candidate for ‘gnu_printf’ format attribute [-Werror=suggest-attribute=format] Fix the compilation errors (`make W=1` when CONFIG_WERROR=y, which is default) by adding __printf() attribute. Signed-off-by: Andy Shevchenko <[email protected]> --- lib/vsprintf.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/lib/vsprintf.c b/lib/vsprintf.c index 56fe96319292..8ebb5f866b08 100644 --- a/lib/vsprintf.c +++ b/lib/vsprintf.c @@ -2419,7 +2419,7 @@ char *rust_fmt_argument(char *buf, char *end, void *ptr); * from Rust code to format core::fmt::Arguments. Do *not* use it from C. * See rust/kernel/print.rs for details. */ -static noinline_for_stack +static noinline_for_stack __printf(1, 0) char *pointer(const char *fmt, char *buf, char *end, void *ptr, struct printf_spec spec) { -- 2.47.2
