****************************************
* LUG meet on 12 Jan. 2003 @ VJTI
****************************************
You can rewrite the same program as follows
-----------------------------------
#!/bin/bash
count=0
var="arg"
while test $# -ne 0 ; do
count=$[ $count + 1 ]
if test $cmd -eq -1 ; then
shift
arg1=$1
echo $arg1
fi
done
-----------------------------------
Couple of points.
Instead of using expr you can use bash' inbuilt expression evaluator using
$[ and ]. Also use "test <condition>" instead of "`test <condition>`" again
using inbuilt test.
Amitay.
On Mon, Dec 16, 2002 at 09:59:13PM +0530, Nikhil Joshi wrote:
> ****************************************
> * LUG meet on 12 Jan. 2003 @ VJTI
> ****************************************
>
> Hi!
>
> I'm trying to take command line args with the help of a bash script
> But i'm not able to achieve it
> Pls guide.
>
> #!/bin/bash
> # i want to detect command line options
> # e.g. sample.sh -1 foo1 -2 foo2 -3 foo3
> # then i want following : arg1=foo1, arg2=foo2 , arg3=foo3
> # I tried following but arg1 takes the value $2, arg2 $3 and arg3 $3
>
>
> count=0 # counter to track current command line arg
>
> for cmd in $@
> do
> count=`expr $count + 1` # count = count + 1
> if `test $cmd = -1`
> then
> arg1=$`expr $count + 1`
> echo $arg1 # unfortunately it gives $2 and not foo1
> fi
> done
>
>
>
>
>
>
> --
> _______________________________________________
>
> http://mm.ilug-bom.org.in/mailman/listinfo/linuxers
>
>
>
Amitay.
--
Eighty percent of married men cheat in America. The rest cheat in Europe.
- Jackie Mason
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