**************************************** * LUG meet on 12 Jan. 2003 @ VJTI ****************************************
> -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED]]On Behalf > Of Nikhil Joshi > Sent: Monday, December 16, 2002 9:59 PM > To: ilug > Subject: [ILUG-BOM] Bash script doubt > > > **************************************** > * LUG meet on 12 Jan. 2003 @ VJTI > **************************************** > > Hi! > > I'm trying to take command line args with the help > of a bash script > But i'm not able to achieve it > Pls guide. > > #!/bin/bash > # i want to detect command line options > # e.g. sample.sh -1 foo1 -2 foo2 -3 foo3 > # then i want following : arg1=foo1, arg2=foo2 , > arg3=foo3 > # I tried following but arg1 takes the value $2, > arg2 $3 and arg3 $3 > > > count=0 # counter to track current command line arg > > for cmd in $@ > do > count=`expr $count + 1` # count = count + 1 > if `test $cmd = -1` > then > arg1=$`expr $count + 1` > echo $arg1 # unfortunately it gives $2 and not foo1 > fi > done > An easy solution is to use getopts. use help command for that. ( help getopts ) This gives the arguments in $1, $2, $3 while $# contains the number of arguments. Hth ===== -- KD. www.kirandivekar.cjb.net __________________________________________________ Do you Yahoo!? Yahoo! Mail Plus - Powerful. Affordable. Sign up now. http://mailplus.yahoo.com -- _______________________________________________ http://mm.ilug-bom.org.in/mailman/listinfo/linuxers
