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* LUG meet on 12 Jan. 2003 @ VJTI
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Hi,
You could use this too
#!/bin/bash
#
# e.g. sample.sh foo1 foo2 foo3
# then the following will happen : arg[0]=foo1, arg[1]=foo2 , arg[2]=foo3
#
count=0 # Counts the number of parameters
until [ -z "$1" ] # loop until all the parameters are usedup
do
arg[$count]=$1 # the $arg[] is like a normal array and
# $1 is the first argument to the script
echo -en "Argument $count is $arg[$count]\n" # Debug Output
count=$(($count+1))
shift # shifts the argument number by one thus
# now $1 is argument number two rather being argument one
done
thanks
Ripunjay Bararia
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]On Behalf Of Nikhil Joshi
Sent: Monday, December 16, 2002 9:59 PM
To: ilug
Subject: [ILUG-BOM] Bash script doubt
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* LUG meet on 12 Jan. 2003 @ VJTI
****************************************
Hi!
I'm trying to take command line args with the help of a bash script
But i'm not able to achieve it
Pls guide.
#!/bin/bash
# i want to detect command line options
# e.g. sample.sh -1 foo1 -2 foo2 -3 foo3
# then i want following : arg1=foo1, arg2=foo2 , arg3=foo3
# I tried following but arg1 takes the value $2, arg2 $3 and arg3 $3
count=0 # counter to track current command line arg
for cmd in $@
do
count=`expr $count + 1` # count = count + 1
if `test $cmd = -1`
then
arg1=$`expr $count + 1`
echo $arg1 # unfortunately it gives $2 and not foo1
fi
done
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