> On Thu, May 28, 1998 at 10:23:12AM -0500, Adam Bailey wrote:
>
> > Let's say the average email is 5k. I did a random sampling in my AOL
> > mailbox, and it seemed to work out to that. And let's say we want to
> > increase that absurdly small 550 to 600, a minor improvement. 50 messages
> > X 5k = 250k * (12,000,000 members * 1.2 average screen names per members
> > (1997) = 14,400,000) = 3,525,000,000. That's 3.5 gigabytes for just an
> > extra 50 5k messages.
>
> Wow, a whole $200 worth of disk. I can see why AOL wouldn't want to make that
> kind of investment. :-)
>
I think you missed a factor of 1,000. it is 3.6 terabytes, or 3600 gigabytes.
I don't think you would have to spend $200,000 to get that much, but it is not
a trivial amount of money for a very small increment.
-phil
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--
J. Philip Miller, Professor, Division of Biostatistics, Box 8067
Washington University School of Medicine, St. Louis MO 63110
[EMAIL PROTECTED] - (314) 362-3617 [362-2693(FAX)]
http://www.biostat.wustl.edu/~phil
