Jim Lynch wrote:
> Ben Okopnik wrote:
>   
>> This is the approach that I'll be taking (I like the way you think, Jim:
>> it's brilliant, since it matches my own mental pretzel-bending... :) The
>> only problem _there,_ as you can probably guess, is resistor wattage:
>> the running current on this motor seems to be about 1.5A, I need to
>> limit it to ~700mA (that being the specified running current of the old
>> motor), so it seems like I need to experiment with 4-8 ohm resistors -
>> which, according to Dr. Ohm, will require a _minimum_ wattage of 8-12W.
>> Good engineering practice makes that 16-24W.
>>
>> In other words, *YIKES*. :)
>>
>>   
>>     
> Well, if you don't mind a series/parallel array I see on ebay
>
> LOT OF 25, 3 OHM 10 WATT 10W WIREWOUND RESISTOR, LOT#67 
> <http://cgi.ebay.com/LOT-OF-25-3-OHM-10-WATT-10W-WIREWOUND-RESISTOR-LOT-67_W0QQitemZ370143952279QQcmdZViewItemQQptZLH_DefaultDomain_0?hash=item562e4c7d97&_trksid=p3286.c0.m14&_trkparms=65%3A12%7C66%3A2%7C39%3A1%7C72%3A1205%7C240%3A1318%7C301%3A1%7C293%3A1%7C294%3A50>
>
> For only $10.
>
> Jim.
>   
So to get a 6 ohm resistor at 18 watts you'd  take 4 of these in series 
in parallel with 4 more in series.  That would give you 6 ohms at 20 
watts.   3 x 4 = 12 in each leg and two of those in parallel would be 6 
ohms.  Resistors in parallel add power so you'd have 10 watts x 2, or 20 
watts.

Seems cheap enough to me. 

Jim.
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