Dear Shri, Thanks a lot. I have tried finding the jacobian matrix when i ran the power flow on case 9 in the example cases given in matlab. I assigned fullJac to be = 1. However, I obtained the following values for J: J =
(1,1) 17.1204 (4,1) -17.1204 (10,1) 0.7195 (13,1) 0.7195 (2,2) 15.8554 (8,2) -15.8554 (11,2) 1.6300 (17,2) 1.6300 (3,3) 17.1013 (6,3) -17.1013 (12,3) 0.8500 (15,3) 0.8500 (1,4) -17.1204 (4,4) 38.2940 (5,4) -10.0631 (9,4) -10.9179 (10,4) -0.7195 (13,4) -3.2220 (14,4) 2.1536 (18,4) 1.6615 (4,5) -10.1682 (5,5) 15.3734 (6,5) -5.5701 (13,5) 1.5848 (14,5) -3.9680 (15,5) 0.6817 (3,6) -17.1013 (5,6) -5.3103 (6,6) 32.3713 (7,6) -9.6479 (12,6) -0.8500 (14,6) 1.8143 (15,6) -2.4536 (16,6) 1.3623 (6,7) -9.6999 (7,7) 22.9890 (8,7) -13.5172 (15,7) 0.9218 (16,7) -3.6932 (17,7) 0.8399 (2,8) -15.8554 (7,8) -13.3411 (8,8) 35.1757 (9,8) -5.4819 (11,8) -1.6300 (16,8) 2.3309 (17,8) -2.7834 (18,8) 1.9295 (4,9) -11.0054 (8,9) -5.8031 (9,9) 16.3998 (13,9) 0.9177 (17,9) 0.3135 (18,9) -3.5910 (1,10) 0.7195 (4,10) -0.7195 (10,10) 17.6018 (13,10) -17.1204 (2,11) 1.6300 (8,11) -1.6300 (11,11) 16.1446 (17,11) -15.8554 (3,12) 0.8500 (6,12) -0.8500 (12,12) 17.0284 (15,12) -17.1013 (1,13) 0.7290 (4,13) 3.2644 (5,13) -2.1820 (9,13) -1.6834 (10,13) -17.3458 (13,13) 38.7981 (14,13) -10.1956 (18,13) -11.0616 (4,14) -1.6246 (5,14) 2.2225 (6,14) -0.6989 (13,14) -10.4239 (14,14) 15.1448 (15,14) -5.7102 (3,15) 0.8471 (5,15) -1.8082 (6,15) 2.4453 (7,15) -1.3577 (12,15) -17.0438 (14,15) -5.2924 (15,15) 32.2624 (16,15) -9.6154 (6,16) -0.9353 (7,16) 1.7179 (8,16) -0.8521 (15,16) -9.8411 (16,16) 22.6136 (17,16) -13.7140 (2,17) 1.6362 (7,17) -2.3398 (8,17) 2.7940 (9,17) -1.9369 (11,17) -15.9161 (16,17) -13.3922 (17,17) 35.3104 (18,17) -5.5029 (4,18) -0.9583 (8,18) -0.3274 (9,18) 1.1393 (13,18) -11.4924 (17,18) -6.0599 (18,18) 16.0813 I was wondering why some of the values are missing and why it is an 18*18 matrix. What I want is J4 for each bus, in order to find the voltage sensitivity. I will be extremely grateful if you could please help me out as my project deadline is next week. Thank you Hiranya On 2 Jun 2015, at 17:08, Abhyankar, Shrirang G. <[email protected]> wrote: > fullJac is a flag that you can set to either access the full Jacobian > matrix or a partial Jacobian. With fullJac = 1, the routine returns the > full Jacobian that has partial derivatives of the power flow equations > w.r.t to the voltage magnitudes and angles at all buses. If fullJac = 0 or > not given, the Jacobian as used for the power flow calculation, i.e., > Jacobian ignoring reactive power equations and voltage magntidues at PV > buses, real, reactive power equations, voltage magnitudes and angles at > swing buses. > > Shri > > -----Original Message----- > From: Hiranya Seneviratne <[email protected]> > Reply-To: MATPOWER discussion forum <[email protected]> > Date: Tuesday, June 2, 2015 at 10:44 AM > To: MATPOWER discussion forum <[email protected]> > Subject: Re: Jacobian matrix values > >> Thank you. >> However what is fulljac? As I am unable to find the value for that. >> Thank you >> >> Sent from my iPhone >> >>> On 2 Jun 2015, at 16:29, "Abhyankar, Shrirang G." <[email protected]> >>> wrote: >>> >>> http://www.pserc.cornell.edu//matpower/docs/ref/matpower5.1/makeJac.html >>> >>> >>> -----Original Message----- >>> From: Hiranya Seneviratne <[email protected]> >>> Reply-To: MATPOWER discussion forum <[email protected]> >>> Date: Tuesday, June 2, 2015 at 4:04 AM >>> To: MATPOWER discussion forum <[email protected]> >>> Subject: Jacobian matrix values >>> >>>> Dear Ray, >>>> Is it possible to find out the values of the jacobian matrix once the >>>> power flow is calculated in Matpower? >>>> Thank you >>>> Hiranya >>>> >>>> Sent from my iPhone >>> >>> >>> >> > > >
