The Jacobian is stored in a sparse matrix format. The Jacobian values not
displayed are all zeros.
MATPOWER orders the Jacobian as follows:
J = [dP_dVa dP_dVm
dQ_dVa dQ_dVm]
where P and Q are the real and reactive power mismatch equations and Va,
Vm are the voltage angles and magnitudes of the buses. The size of the
Jacobian is 2*nbus X 2*nbus where nbus is the number of buses.
If you only want the sensitivities w.r.t. voltage magnitudes then extract
the dQ_dVm sub-matrix from the Jacobian.
Shri
-----Original Message-----
From: Hiranya Seneviratne <[email protected]>
Reply-To: MATPOWER discussion forum <[email protected]>
Date: Tuesday, June 2, 2015 at 4:54 PM
To: MATPOWER discussion forum <[email protected]>
Subject: Re: Jacobian matrix values
>Dear Shri,
>
>Thanks a lot. I have tried finding the jacobian matrix when i ran the
>power flow on case 9 in the example cases given in matlab.
>I assigned fullJac to be = 1.
>However, I obtained the following values for J:
>J =
>
> (1,1) 17.1204
> (4,1) -17.1204
> (10,1) 0.7195
> (13,1) 0.7195
> (2,2) 15.8554
> (8,2) -15.8554
> (11,2) 1.6300
> (17,2) 1.6300
> (3,3) 17.1013
> (6,3) -17.1013
> (12,3) 0.8500
> (15,3) 0.8500
> (1,4) -17.1204
> (4,4) 38.2940
> (5,4) -10.0631
> (9,4) -10.9179
> (10,4) -0.7195
> (13,4) -3.2220
> (14,4) 2.1536
> (18,4) 1.6615
> (4,5) -10.1682
> (5,5) 15.3734
> (6,5) -5.5701
> (13,5) 1.5848
> (14,5) -3.9680
> (15,5) 0.6817
> (3,6) -17.1013
> (5,6) -5.3103
> (6,6) 32.3713
> (7,6) -9.6479
> (12,6) -0.8500
> (14,6) 1.8143
> (15,6) -2.4536
> (16,6) 1.3623
> (6,7) -9.6999
> (7,7) 22.9890
> (8,7) -13.5172
> (15,7) 0.9218
> (16,7) -3.6932
> (17,7) 0.8399
> (2,8) -15.8554
> (7,8) -13.3411
> (8,8) 35.1757
> (9,8) -5.4819
> (11,8) -1.6300
> (16,8) 2.3309
> (17,8) -2.7834
> (18,8) 1.9295
> (4,9) -11.0054
> (8,9) -5.8031
> (9,9) 16.3998
> (13,9) 0.9177
> (17,9) 0.3135
> (18,9) -3.5910
> (1,10) 0.7195
> (4,10) -0.7195
> (10,10) 17.6018
> (13,10) -17.1204
> (2,11) 1.6300
> (8,11) -1.6300
> (11,11) 16.1446
> (17,11) -15.8554
> (3,12) 0.8500
> (6,12) -0.8500
> (12,12) 17.0284
> (15,12) -17.1013
> (1,13) 0.7290
> (4,13) 3.2644
> (5,13) -2.1820
> (9,13) -1.6834
> (10,13) -17.3458
> (13,13) 38.7981
> (14,13) -10.1956
> (18,13) -11.0616
> (4,14) -1.6246
> (5,14) 2.2225
> (6,14) -0.6989
> (13,14) -10.4239
> (14,14) 15.1448
> (15,14) -5.7102
> (3,15) 0.8471
> (5,15) -1.8082
> (6,15) 2.4453
> (7,15) -1.3577
> (12,15) -17.0438
> (14,15) -5.2924
> (15,15) 32.2624
> (16,15) -9.6154
> (6,16) -0.9353
> (7,16) 1.7179
> (8,16) -0.8521
> (15,16) -9.8411
> (16,16) 22.6136
> (17,16) -13.7140
> (2,17) 1.6362
> (7,17) -2.3398
> (8,17) 2.7940
> (9,17) -1.9369
> (11,17) -15.9161
> (16,17) -13.3922
> (17,17) 35.3104
> (18,17) -5.5029
> (4,18) -0.9583
> (8,18) -0.3274
> (9,18) 1.1393
> (13,18) -11.4924
> (17,18) -6.0599
> (18,18) 16.0813
>
>
>
>I was wondering why some of the values are missing and why it is an 18*18
>matrix.
>
>What I want is J4 for each bus, in order to find the voltage sensitivity.
>I will be extremely grateful if you could please help me out as my
>project deadline is next week.
>
>Thank you
>Hiranya
>On 2 Jun 2015, at 17:08, Abhyankar, Shrirang G. <[email protected]> wrote:
>
>> fullJac is a flag that you can set to either access the full Jacobian
>> matrix or a partial Jacobian. With fullJac = 1, the routine returns the
>> full Jacobian that has partial derivatives of the power flow equations
>> w.r.t to the voltage magnitudes and angles at all buses. If fullJac = 0
>>or
>> not given, the Jacobian as used for the power flow calculation, i.e.,
>> Jacobian ignoring reactive power equations and voltage magntidues at PV
>> buses, real, reactive power equations, voltage magnitudes and angles at
>> swing buses.
>>
>> Shri
>>
>> -----Original Message-----
>> From: Hiranya Seneviratne <[email protected]>
>> Reply-To: MATPOWER discussion forum <[email protected]>
>> Date: Tuesday, June 2, 2015 at 10:44 AM
>> To: MATPOWER discussion forum <[email protected]>
>> Subject: Re: Jacobian matrix values
>>
>>> Thank you.
>>> However what is fulljac? As I am unable to find the value for that.
>>> Thank you
>>>
>>> Sent from my iPhone
>>>
>>>> On 2 Jun 2015, at 16:29, "Abhyankar, Shrirang G." <[email protected]>
>>>> wrote:
>>>>
>>>>
>>>>http://www.pserc.cornell.edu//matpower/docs/ref/matpower5.1/makeJac.htm
>>>>l
>>>>
>>>>
>>>> -----Original Message-----
>>>> From: Hiranya Seneviratne <[email protected]>
>>>> Reply-To: MATPOWER discussion forum <[email protected]>
>>>> Date: Tuesday, June 2, 2015 at 4:04 AM
>>>> To: MATPOWER discussion forum <[email protected]>
>>>> Subject: Jacobian matrix values
>>>>
>>>>> Dear Ray,
>>>>> Is it possible to find out the values of the jacobian matrix once the
>>>>> power flow is calculated in Matpower?
>>>>> Thank you
>>>>> Hiranya
>>>>>
>>>>> Sent from my iPhone
>>>>
>>>>
>>>>
>>>
>>
>>
>>
>
>
>
