Hi Ray, Thank you for your email.
Kind Regard, Mohammad Ammar Raza On 17 May 2017 at 14:51, Ray Zimmerman <r...@cornell.edu> wrote: > Hi Mohammad, > > A unit commitment problem with quadratic generator costs or ramping costs > requires a solver that can handle Mixed Integer Quadratic Programming > (MIQP) problems. The only MATPOWER-compatible solvers that handle MIQP are > Gurobi, CPLEX and MOSEK, as stated in the System Requirements section of > the MOST User’s Manual. > > So, you will either need to install one of these solvers, or modify your > problem so that in does not include any quadratic costs. > > Ray > > > On May 16, 2017, at 5:30 PM, Ammar Raza <ammaraz...@gmail.com> wrote: > > Hi > > I am trying to do example 6 of the MOST user manual with Bus 118 and I got > this error. > > Error using mpopt2qpopt (line 92) > mpopt2qpopt: Sorry, no solver available for MIQP models > > Error in most (line 2065) > mdo.QP.opt = mpopt2qpopt(mpopt, model, 'most'); > > Error in most_ammar6 (line 108) > mdo = most(mdi, mpopt); > > > Kind Regard, > > Mohammad Ammar Raza > > > > > On 15 May 2017 at 20:14, Ray Zimmerman <r...@cornell.edu> wrote: > >> In a deterministic problem, transmat can simply be a scalar with the >> number of periods. See the description of transmat in the help for >> loadmd() >> <http://www.pserc.cornell.edu/matpower/docs/ref/matpower6.0/most/loadmd.html> >> . >> >> Ray >> >> >> >> On May 15, 2017, at 7:37 AM, Ammar Raza <ammaraz...@gmail.com> wrote: >> >> Thank you Ray >> >> Therefore, Transmat should be like that? >> >> transmat = cell(1, nt); >> T = [ 1x 99]; >> [transmat{:}] = deal(T * ones(1,1)); >> transmat{1} = T; >> >> Kind Regard, >> >> Mohammad Ammar Raza >> >> >> >> >> On 11 May 2017 at 13:42, Ray Zimmerman <r...@cornell.edu> wrote: >> >>> Just to clarify, if loadprofile.rows = 0, then loadprofile.values(:, >>> 1, :) = [24 x 1] and all loads are scaled together. Otherwise, the >>> number of columns in loadprofile.values(:, 1, :) must equal the length >>> of loadprofile.rows and each of the specified loads is scaled >>> separately. >>> >>> Ray >>> >>> >>> On May 9, 2017, at 10:29 AM, Ammar Raza <ammaraz...@gmail.com> wrote: >>> >>> Its means >>> >>> loadprofile.rows= [1 x 99 ] >>> >>> Thanks Stephanie for your help. >>> >>> Kind Regard, >>> >>> Mohammad Ammar Raza >>> >>> >>> >>> >>> On 9 May 2017 at 15:25, Stephanie <myvog...@gmail.com> wrote: >>> >>>> Yes, and the value of rows, 0 means the load is applied to the all >>>> buses, so you should also change the value of the rows by >>>> loadprofile.rows=load_index >>>> (e.g. loadprofile.rows=[2 3 5]), if there are three loads located in bus 2, >>>> 3 and 5, respectively) >>>> >>>> Best Regards, >>>> Stephanie >>>> >>>> 2017-05-09 22:09 GMT+08:00 Ammar Raza <ammaraz...@gmail.com>: >>>> >>>>> that means >>>>> >>>>> loadprofile = struct( ... >>>>> 'type', 'mpcData', ... >>>>> 'table', CT_TLOAD, ... >>>>> 'rows', 0, ... >>>>> 'col', CT_LOAD_ALL_PQ, ... >>>>> 'chgtype', CT_REP, ... >>>>> 'values', [] ); >>>>> >>>>> loadprofile.values(:, 1, :) = [ 24 x 99 ] >>>>> >>>>> >>>>> Kind Regard, >>>>> >>>>> Mohammad Ammar Raza >>>>> >>>>> >>>>> >>>>> >>>>> On 9 May 2017 at 14:55, Stephanie <myvog...@gmail.com> wrote: >>>>> >>>>>> Hi, >>>>>> >>>>>> I tried it a few days before, what I did is: >>>>>> >>>>>> loadprofile.rows=load_index; %which applies the load to the bus it >>>>>> locates >>>>>> loadprofile.value (:,1,:) = [24 x 99]; >>>>>> >>>>>> And it works in my situation >>>>>> >>>>>> Hope it will help you >>>>>> ------------------------------ >>>>>> Best Regards >>>>>> Stephanie >>>>>> >>>>>> >>>>>> *From:* Ammar Raza <ammaraz...@gmail.com> >>>>>> *Date:* 2017-05-09 21:43 >>>>>> *To:* MATPOWER discussion forum <matpowe...@list.cornell.edu> >>>>>> *Subject:* MOST >>>>>> Hi all, >>>>>> >>>>>> I am working on bus 118 with 54 generator and 99 loads. >>>>>> >>>>>> I would like to ask you for the multi period problem i.e. 24 hours, >>>>>> how I will make the load profile function. Can I do like that >>>>>> >>>>>> loadprofile.value (:,1,1) = [24 x 99]; >>>>>> >>>>>> >>>>>> >>>>>> As in case3a in the MOST manual there is only one load therefore, >>>>>> load profile matrix is [12 x 1] >>>>>> >>>>>> loadprofile.value(:,1,1)=[ >>>>>> 440; >>>>>> 480; >>>>>> .. >>>>>> .. >>>>>> .. ]; >>>>>> >>>>>> >>>>>> Kind Regard, >>>>>> >>>>>> Mohammad Ammar Raza >>>>>> >>>>>> >>>>>> >>>>>> >>>>> >>>> >>> >>> >> >> > >
