Dear users, I would like to obtain a better understanding of the Gaussian source function used in MEEP, so I have some simple questions concerning the equation for the Gaussian source presented in the online reference manual.
(1) The equation as written is not set equal anything. Is it actually equal to the complex value of the field or current component used as the source, e.g., Jz? (2) Is "Omega" equal to 2*pi*(center frequency)? (3) When considering the "Cutoff" parameter, are the widths in terms of time (1/fwidth) = "width"? I am trying to plot my Gaussian function, so I need to ensure that I comprehend MEEP's input in light of the referenced Gaussian equation. Thanks very much. Doug Nance _______________________________________________ meep-discuss mailing list meep-discuss@ab-initio.mit.edu http://ab-initio.mit.edu/cgi-bin/mailman/listinfo/meep-discuss
