Thanks Errol, I see how it works now, much the same as the mph method but using this method you have to convert at the end - I was using the wrong units for the circumference.
regards Terry -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of E Smith Sent: Saturday, 16 February 2002 9:39 AM To: [EMAIL PROTECTED] Subject: RE: Boot Release Terry, This is for kph in any gear. (((60/diff ratio) x tire circumference)/gear ratio) Divide 60 by the diff ratio, then multiply that answer by the circumference of the tyre in metres. Divide that answer by the gear ratio for the gear being used = kph in that gear. Eg. 60/3.7(diff ratio) =16.216. 16.216 X 1.83 metres circumference (205/60x13 tyre) = 29.675 this is kph for 1:1 gear (4th) For other gears divide by the gear ratio eg for 0.864 5th box 29.675/0.864= 34.346 kph For 1st gear 29.675/3.362=8.821kph etc Cheers Feral Errol --membersozdat------------------------------------------------------- OZDAT Mailing List Please Note:- Send (un)subscribe requests to [EMAIL PROTECTED] Send submissions to [EMAIL PROTECTED] No unauthorised redistribution of this email http://www.ozdat.com/ozdatonline/index.htm http://www.ozdat.com/ozdatonline/listindex.html http://www.mail-archive.com/[email protected]/ ---------------------------------------------------------------------
