Hi Martin
Thans for your reply and sorry for my late response.
In fact I am looking into 'Kinetic energy conversion' and
not 'Potential/head energy conversion'. I know that's a bit
unconventional, but do you think that is totally
impossible/impractical to do ?
Thanks
Jahangir.
--- In [EMAIL PROTECTED], "Martin.Leahy"
<[EMAIL PROTECTED]> wrote:
>
> Most waterpower systems require that you concentrate most of the
practical
> head (fall) between the entry (high) point and the exit back to
the stream
> (low point). i.e. one is attempting to harness the potential
energy of the
> water falling from high point to low point. [Harnessing the
kinetic (speed)
> energy is a different and less used approach]
>
> Power available is then:
>
> Power (kW) = flow (m3/s) x head (m) x g (m/s^2) x overall
efficiency
>
> where g is the acceleration due to gravity.
>
> or say power (kW) = flow (m3/s) x head (m) x 7
>
> The units one buys and sells electricity are kWh (i.e. the number
of kW
> times the hours of operation at that power level). Cost effective
systems
> will usually have a 30-40% capacity factor (i.e. the power output
in an
> average year would be nameplate power x hours in the year x 0.4).
>
> You need to measure the head, and the more (financial/time) risk
you take
> the more confident you need to be about the accuracy of the head
and flow
> you measure!
>
> Regards,
>
> Martin
>
> -----Original Message-----
> From: Mohammad Jahangir Khan [mailto:[EMAIL PROTECTED]
> Sent: 01 November 2004 14:08
> To: [EMAIL PROTECTED]
> Subject: [microhydro] Newbie question: energy estimation from flow
rate
>
>
>
>
>
> Hi
>
> Is it possible to measure the energy/power available from a free-
> flowing water stream ? The flow-rate is given in m3/s.
>
> Thanks.
> J. Khan
>
>
>
>
>
>
>
>
>
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