在 2023-03-29 21:33, Corinna Vinschen 写道:
I don't think this is correct.  Multiple backslashes are folded into a
single backslash by the Windows API layer.  Thus \\host\\share is not
equivalent to

   \\host\<empty-share>\<dir-called-share>

but to

   \\host\share

Try this example, please:

Well, I didn't use `GetFinalPathNameByHandle()`, but examined these paths in 
CMD:

   C:\>dir \\192.168.1.8\\temp_share
   The specified path is invalid.

   C:\>dir \\192.168.1.8\temp_share
   (... directory contents follow ...)


As you can see, if we assume that CMD doesn't do path resolution itself, these 
paths are not equivalent.


--
Best regards,
LIU Hao

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