>From 1.2 docs:
var obj1 = {a: 0, b: 1};
var obj2 = {c: 2, d: 3};
var obj3 = {a: 4, d: 5};
var merged = $merge(obj1, obj2, obj3); //returns {a: 4, b: 1, c: 2, d:
5}, (obj1, obj2, and obj3 are unaltered)
var nestedObj1 = {a: {b: 1, c: 1}};
var nestedObj2 = {a: {b: 2}};
var nested = $merge(nestedObj1, nestedObj2); //returns: {a: {b: 2, c: 1}}
On Tue, Oct 12, 2010 at 4:44 PM, Ryan Florence <[email protected]> wrote:
> From the 1.3 docs:
>
> var obj1 = {a: 0, b: 1};
> var obj2 = {c: 2, d: 3};
> var obj3 = {a: 4, d: 5};
> var merged = Object.merge(obj1, obj2, obj3); // returns {a: 4, b: 1, c: 2, d:
> 5}, (obj2, and obj3 are unaltered)
>
> merged === obj1; // true, obj1 gets altered and returned as merged object
>
> var nestedObj1 = {a: {b: 1, c: 1}};
> var nestedObj2 = {a: {b: 2}};
> var nested = Object.merge(nestedObj1, nestedObj2); // returns: {a: {b: 2, c:
> 1}}
>
>
>
> On Oct 12, 2010, at 3:39 PM, Oskar Krawczyk wrote:
>
> Ouch.
>
> Yes, this should not happen.
>
> Can you post a ticket on lighthouse?
>
> On 2010-10-12, at 23:32, atom wrote:
>
> bit of unexpected behavior (which might be intentional). When using
>
> Object.merge the objects I pass in are being altered, unlike how
>
> $merge used to behave.
>
>
> old way:
>
>
> var obj1 = {a: 1, b: 2, c: 3}
>
> var obj2 = {d: 4, e: 5, f: 6}
>
> var merged = $merge(obj1, obj2);
>
> console.log(obj1); // returns {a: 1, b: 2, c: 3}
>
>
> new way:
>
>
> var obj1 = {a: 1, b: 2, c: 3}
>
> var obj2 = {d: 4, e: 5, f: 6}
>
> var merged = Object.merge(obj1, obj2);
>
> console.log(obj1); // returns {a: 1, b: 2, c: 3, d: 4, e: 5, f: 6}
>
>
>
>
